Home
Class 12
CHEMISTRY
Using valence bond theory explain geomet...

Using valence bond theory explain geometry, hybridisation and magnetic property of `[CoF_6]_3^-` (Atomic number of Co = 27).

Text Solution

Verified by Experts

`[CoF_6]_3^-` In this complex, Co is present as ` Co^3+`. Outer configuration of `Co^3+ = 3d^6 4s^0` `F^-` is a weak field ligand, so no pairing occurs and thus, `F^-` occupy nd orbitals as because of the presence of four unpaired electrons, the complex is paramagnetic.
Promotional Banner

Topper's Solved these Questions

  • SUPPLEMENTARY EXAMINIATION QUESTION PAPER JUNE 2017

    SUBHASH PUBLICATION|Exercise PART D|5 Videos
  • SUPPLEMENTARY EXAMINIATION QUESTION PAPER JUNE 2017

    SUBHASH PUBLICATION|Exercise PART E|22 Videos
  • SUPPLEMENTARY EXAMINIATION QUESTION PAPER JUNE 2017

    SUBHASH PUBLICATION|Exercise PART B|8 Videos
  • SUPPLEMENTARY EXAMINATION QUESTION PAPER JUNE 2019

    SUBHASH PUBLICATION|Exercise PART-D|11 Videos
  • SURFACE CHEMISTRY

    SUBHASH PUBLICATION|Exercise Questions|79 Videos

Similar Questions

Explore conceptually related problems

Explain the hybridisation, geometry and magnetic property of [CoF_(6)]^(3-) based on VBT.

Using VBT, explainthe geometry and magnetic property of [Ni(CN)_(4)]^(-2) . (Atomic Number of Ni=28).

Using valence bond theory account for the geometry and magnetic nature of [NiCl_(4)]^(2-) ion. ("Atomic number of Ni "= 28) .

Using valence bond theory (VBT), account for the geometry, type of hybridization and magnetic property of [NiCl_(4)]^(2-) .

Explain the hybridisation, geometry and magnetic property of [Ni(Cl)_(4)]^(2-) .

Using VBT, explain the geometry and magnetic property of [NiCl^(4)]^(-2) given atomic number of Ni=28.