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The vapour pressure of pure benzene at a...

The vapour pressure of pure benzene at a certain tempreature is 0.850 bar. A non-volatile. non-electrolyte solid weighing 0.5g, when added to 39.0g of benzene (molar mass of benzene 78g `mol^-1`) vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance?

Text Solution

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`(P^0-P)/(p^0)`= `(W_2timesM_1)/(W_1timesM_2)` ` M_2 = (0.5times78)/(39times[(0.850-0.845)/0.850])= 170 g mol^-1`
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