`(0.8x-0.5y)(1.5x-3y)`

The linear system of equations {:(8x-3y-5z=0),(5x-8y+3z=0),(3x+5y-8z=0):}} has

Solve for x and y: 0.4x-1.5y=6.5, 0.3x+0.2y=0.9

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

The equation of straight line belonging to both the families of lines (x-y+1)+lambda_1(2x-y-2)=0 and (5x+3y-2)+lambda_2(3x-y-4)=0 where lambda_1, lambda_2 are arbitrary numbers is (A) 5x -2y -7=0 (B) 2x+ 5y - 7= 0 (C) 5x + 2y -7 =0 (D) 2x- 5y- 7= 0

Find the following products: (6x)/5(x^3+y^3) (ii) x y(x^3-y^3) (iii) 0. 1 y(0. 1 x^5+0. 1 y)

If {:2[(3,4),(5,x)] + [(1,y ),(0,1)] = [(7,0),(10,5)] , find (x-y).

If (-2,1) is the centroid of the triangle having its vertices at (x,0),(5,-2),(-8,y), then x,y satisfy the relation 3x+8y=0 (b) 3x-8y=0( c) 8x+3y=0 (d) 8x=3y