`tan (e^x+5)`

int frac{e^x(1+x)}{ cos^2 (x e^x)} dx=.............. A) tan(x e^x ) + c B) - tan(x e^x ) + c C) cot(x e^x ) + c D) -cot(x e^x ) + c

int( e^x(1+x))/(cos ^2(e^x x)) d x equals a) -cot (e x^x)+ C b) tan (x e^x)+C c) tan (e^x)+C d) cot (e^x)+C

int e^(x)tan e^(x)dx

int e^(x)tan(e^(x))dx

integrated e ^ (x) (log sin e ^ (x)) / (tan e ^ (x))

int e^(x)sec e^(x)tan e^(x)dx

underset(x to 0)"Lt" (e^(tan x)-e^(x))/(tan x-x)=

Integrate int e^x tan e^x dx .

Let f(x)=(e^(tan x)-e^(x)+ln(sec x+tan x)-x)/(tan x-x) be a continuous function at x=0. The value f(0) equals

Prove that int e^x (tan^-1 x+1/(1+x^2)) dx=e^x tan^-1x+c