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In Fig. 9.22, ABCD is a quadrilateral a...

In Fig. 9.22, ABCD is a quadrilateral and `B E\ ||\ A C`and also BE meets DC produced at E. Show that area of `DeltaA D E`is equal to the area of the quadrilateral ABCD.

Text Solution

Verified by Experts

Lets proof BE||AC and take other things given.
area(ABCD)=area(ACD)+area(ABC)
area(ADE)=area(ACD)+area(AEC)
So, area(ABC)=area(AEC)
According theorem 9.2
BE||AC.
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