the equation `(x^2-6x+8)+lambda(x^2-4x+3)=0 ` for ` lambdaepsilonR-{-1}` has

The equation (x^(2)-6x+8)+lambda (x^(2)-4x+3)=0, lambda in R has

The equation x^(2)-6x+8+lambda(x^(2)-4x+3)=0,AA lambda in R-{-1} has

Roots of the equation (x^2-4x+3)+lamda(x^2-6x+8)=0 , lamda in R will be

Roots of the equation (x^(2)-4x+3)+lambda(x^(2)-6x+8)=0lambda in R will be

Roots of the quadratic equation (x^2-4x+3)+lamda(x^2-6x+8)=0,lamdainR will be

The number of real roots of the equation 4x^(3)-x^(2)+lambda^(2)x-mu=0 , mu in R, lambda > 1 is

Consider the biquadratic equation E:x^(4)-5x^(3)+(lambda+2)x^(2)-5x+1=0 then value of lambda so that equation E has two real solutions

The value of lambda in order that the equations 2x^(2)+5 lambda x+2=0 and 4x^(2)+8 lambda x+3=0 have a common root is given by

If the equation |x^2-5x + 6|-lambda x+7 lambda=0 has exactly 3 distinct solutions then lambda is equal to

If the equation |x^2-5x + 6|-lambda x+7 lambda=0 has exactly 3 distinct solutions then lambda is equal to