The rms speed of particle of mass `5 xx 10^(-17) kg`. In their random motion in air at NTP will be (Boltzmann's constant) `K = 1.38 xx 10^(-23) J//K`

Calculate the rms speed of smoke particles of mass 5 xx 10^(-17) kg in their Brownian motion in air at NTP. Given k_(B) = 1.38 xx 10^(-23) J//K

Calculate the rms speed of smoke particles of mass 5 xx 10^(-17) kg in their Brownian motion in air at NTP. Given k_(B) = 1.38 xx 10^(-23) J//K

Fill in the blanks: The value of Boltzmann's constant is 1.38 xx 10^-23 …………

The rms velocity of smoke particles of mass 3 xx 10^(-17) kg. at 27^(@)C in m/sec. is.

The diameter of a gas molecule is 2.4 xx 10^(-10) m . Calculate the mean free path at NTP. Given Boltzmann constant k = 1.38 xx 10^(-23) J molecule^(-1) K^(-1) .

The kinetic energy of translation of an oxygen molecule at a particular temperature of 6.27 xx 10^(-31) J . Calculate the temperature . Boltzman's constant = 1.38 xx 10^(-23) J//K .

A diamtomic gas consisting of rigid molecules is at a temperature of 87^(@)C . If the moment of inertia is 2.76 xx 10^(-39) gcm^(2) , then the rms angular speed of the molecule is (Boltzmann constant = 1.38 xx 10^(-23)JK^(-1) )

If the free electron density of copper is 8.6xx10^(28)m^(-3) and resistivity of copper at room temperature is 1.7xx10^(-6)Omega cm , find the relaxation time for the free electrons of copper. Given, mass of electron =9.1xx10^(-31) kg , and charge of electron =1.6xx10^(-19)C. Boltzmann's constant k = 1.38 xx 10^-23 J K^-1