The height at which the value of `g` is half that on the surface of the earth of radius `R` is

The acceleration due to gravity (g) on the surface of the the earth is 9.8 m/s^2 . At what height 'h' will the value of 'g' be half of that on the surface of the earth?

If R is the radius of the earth, the height at which g will decrease by 0.1% of its value at the surface of the earth is

At what height above the earth surface, the value of g is half of its value on earth's surface ? Given its radius is 6400 km

If radius of earth is R , then the height h at which the value of g becomes (1/49)th of its value at the surface is

If radius of earth is R , then the height h at which the value of g becomes (1/49)th of its value at the surface is

At what height above the earth surface, the acceleration due to gravity will be half that on the surface of earth ? Suppose R is the radius of earth.

Calculate the height from earth’s surface at which value of g is 1% than that of the earth surface.