It `cos(alpha+beta)=4/5,sin(alpha-beta)=5/(13)a n dalpha,beta` lie between `0a n dpi/4` , prove that `tan2alpha=(56)/(33)`

It cos(alpha+beta)=4/5,sin(alpha-beta)=5/(13)and alpha,beta lie between 0a n dpi/4 , prove that tan2alpha=(56)/(33)

If cos (alpha+beta)=4/5, sin (alpha -beta)=5/13 and alpha, beta lie between 0 and pi/4 , prove that tan 2 alpha = 56/33 .

If cos(alpha+beta)=4/5; sin(alpha-beta)=5/13 and alpha,beta lie between 0&pi/4 then find the value of tan2alpha

If cos(alpha+beta)=4/5.sin(alpha-beta)=5/13 and alpha , beta lie between 0 and pi/4 then find the value of tan2alpha

If cos(alpha+beta)=4/5; sin(alpha-beta)=5/13 and alpha,beta lie between 0&pi/4 then find the value of tan2alpha

If cos(alpha+beta)=4/5, sin(alpha-beta)=5/13and alpha, beta between 0 and (pi)/(4),then tan 2 alpha=

cos(alpha-beta)=(3)/(5),sin(alpha+beta)=(5)/(13) then tan2 alpha

If cos(alpha+beta)=(4)/(5);sin(alpha-beta)=(5)/(13) and alpha,beta lie between 0&(pi)/(4) then find the value of tan2 alpha