A block of mass 2 kg is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F = 40 N. The kinetic energy of the particle increases 40 J in a given interval of time. Then, `(g = 10 m//s^(2))`

A block of mass 2 kg is hanging over a smooth and light pulley through a light string. The order end of the string is pulled by a constant force F = 40 N . The kinetic energy of the particle increase 40 J in a given interval of time. Then : (g = 10 m//s^(2)) . .

A block of mass M is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F. The kinetic energy of the block increases by 20 J in 1 s:-

A block of mass M is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F. The kinetic energy of the block increases by 20J in 1s.

A block of mass M is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F. The kinetic energy of the block increases by 20J in 1s.

A block of mass 10 kg is hanging over a smooth and light pulley through a light string and the other end of the string is pulled down by a constant force F. The kinetic energy of the block increases by 20 J in 1 s

A block of mass 10 kg is hanging over a smooth and light pulley through a light string and the other end of the string is pulled down by a constant force F. The kinetic energy of the block increases by 20 J in 1 s