Find the points of contact `Q` and `R` of a tangent from the point `P(2,3)` on the parabola `y^2=4xdot`

Explanation

Let points Q and R be `(t_(1)^(2),2t_(1))and(t_(2)^(2).2t_(2))`.
Point of intersection of tangent at Q and R is `(t_(1)t_(2),(t_(1)+t_(2)))-=(2,3)`.
`:." "t_(1)t_(2)=2andt_(1)+t_(2)=3`.
Solving, we get, `t_(1)=1andt_(2)=2`.
So, Q is (1,2) and R is (4,4).