Constant forces `P_(1)=hati-hatj+hatk, P_(2)= -hati+2hatj-hatik and P_(3)=hatj-hatk` act on a particle at a point A . Determine the work done when particle is displaced from position `A(4hati-3hatj-2hatk) " to" B (6hati+hatj-3hatk)`

Explanation

Resultant force
`vecF = vecP_(1)+vecP_(2)+vecP_(3)=2hatj- hatk`
And displacement = `vecAB`
= P.V. of B-P.V. of A
`= (6hati + hatj - 3hatk) - (4hati - 3hatj - 2hatk) `
`= 2hati + 4hatj -hatk`
(ii) work done = `vecF. vecAB `
=` (2hatj-hatk).(2hati=4hatj - hatk)`
= 9 unit