If `veca` satisfies `vecaxx(hati+2hatj+hatk)=hati-hatk" then " veca` is equal to

Options

A. `lambdahati+(2lambda-1)hatj+lambdahatk,lambda in R`
B. `lambdahati+(1-2lambda)hatj+lambdahatk,lambda in R`
C. `lambdahati+(2lambda+1)hatj+lambdahatk,lambda in R`
D. `lambdahati+(1+2lambda)hatj+lambdahatk,lambda in R`

Answer

c

Explanation

`vecaxx(hati + 2hatj + hatk) = hati-hatk= (hatjxx (hati + 2hatj +hatk))`
`or (veca- hatj) xx (hati + 2hatj +hatk) = vec0`
`or veca - hatj = lambda(hati + 2hatj +hatk)`
`or veca=lambdahati+ (2lambda+1) hatj + lambdahatk , lambda in R`