The figure shows an inductor of `2H` through which a current increasing at the rate of `5A//sec` is flowing.Find the potential difference `V_(X)-V_(Y)`.

A section of an electrical circuit XY is shown in figure-5.100 which carries a current of 5A which is decreasing at the rate of 10 A//s . Find the potential difference V_(y)-V_(x')

When the current in the portion of the circuit shown in the figure is 2A and increasing at the rate of 1A//s ,the measured potential difference V_(a)-V_(b)=8V .However when the current is 2A and decreasing at the rate of 1A//s , the measured potential difference V_(a)-V_(b)=4V .The values of R and L are:

When the current in the portion of the circuit shown in the figure is 2A and increasing at the rate of 1A//s ,the measured potential difference V_(a)-V_(b)=8V .However when the current is 2A and decreasing at the rate of 1A//s , the measured potential difference V_(a)-V_(b)=4V .The values of R and L are:

A current of 2 A flows in a system of conductor as shown. The potential difference (V_(A) - V_(B))

A current of 2 A flows in a system of conductor as shown. The potential difference (V_(A) - V_(B))

A current of 2 A flows in a system of conductor as shown. The potential difference (V_(A) - V_(B))

A current of 2 A flows in a system of conductor as shown. The potential difference (V_(A) - V_(B))

If current is increases with rate of 2 Amp/sec , then find V_A -V_B

If current is increases with rate of 2 Amp/sec , then find V_A -V_B

If the instantaneous change on the capacitor is 100 muC and current through the circuit is decreasing at the rate of 2×10^3 A/s then potential difference V_A-V_B is equal to