A gaseous mixture is composed of equal number of moles of `CH_4, C_2H_6 and C_2H_2`. Determine the average molecular mass of mixture (in amu)

A gaseous mixture contains 40% H_(2) and 60% He, by volume. What is the average molecular mass of mixture ?

In a gaseous mixture, if alkane (C_(x)H_(2x +2)) and alkene (C_(y)H_(2y)) are taken in 2 : 1 mole ratio, the average molecular weight of mixture is observed to be 20. If the same alkane and alkene are taken in 1 : 2 mole ratio, the average molecular weight of mixture of mixture is observed to be 24. Then, the value of 'x' and 'y' and respectively :

In a gasseous mixture, if alkane (C_(x)H_(2x +2)) and alaene (C_(y)H_(2y)) are taken in 2 : 1 mole ratio, the average molecular weight of mixture is observed to be 20. If the same alkane and alkene are taken in 1 : 2 mole ratio, the average molecular weight of mixture of mixture is observed to be 24. Then, the valule of 'x' and 'y' and respectively :

A gaseous mixture contains SO_2 & CO_2 , average molecular mass of mixture may be

A gaseous mixture contains equal mass of CH_(4) and SO_(2) gas. The mole fraction of SO_(2) in the mixture is

Mixture of 1 mole of each CH_(4) and C_(2)H_(6) absorb 5 mole of Cl_(2) to form C Cl_(4) and C_(2)Cl_(6) . Then average molecular wt. of the gaseous mixture is

Mixture of 1 mole of each CH_(4) and C_(2)H_(6) absorb 5 mole of Cl_(2) to form C Cl_(4) and C_(2)Cl_(6) . Then average molecular wt. of the gaseous mixture is