In a triangle `ABC, 2 ac sin (1/2)(A-B + C) =`

In a triangle ABC, 2ac sin ((A-B+C)/2) =

In triangle ABC,2ac sin((1)/(2)(A-B+C)) is equal to a^(2)+b^(2)-c^(2)(b)c^(2)+a^(2)-b^(2)b^(2)-c^(2)-a^(2)(d)c^(2)-a^(2)-b^(2)

In Delta ABC , 2ac sin ""( 1)/(2) (A-B+C)=

In a triangle ABC sin (A/2) sin (B/2) sin (C/2) = 1/8 prove that the triangle is equilateral

In any triangle ABC, show that : 2a sin (B/2) sin (C/2)=(b+c-a) sin (A/2)

In a triangle ABC, sin^(2)A + sin^(2)B + sin^(2)C = 2 , then the triangle is