If `secAtanB+tanAsecB=91`, then the value of `(secAsecB+tanAtanB)^2` is equal to….

If sec A tan B + sec B tan A = 91 then the value of (secA secB + tanA tan B)^(2) - 91^(2) is equal to

In a A B C , if tanA:tanB :tanC=3:4:5, then the value of sinA sinB sinC is equal to (a) 2/(sqrt(5)) (b) (2sqrt(5))/7 (2sqrt(5))/9 (d) 2/(3sqrt(5))

In a A B C , if tanA:tanB :tanC=3:4:5, then the value of sinA sinB sinC is equal to (a) 2/(sqrt(5)) (b) (2sqrt(5))/7 (c) (2sqrt(5))/9 (d) 2/(3sqrt(5))

In a A B C , if tanA:tanB :tanC=3:4:5, then the value of sinA sinB sinC is equal to (a) 2/(sqrt(5)) (b) (2sqrt(5))/7 (2sqrt(5))/9 (d) 2/(3sqrt(5))

In a A B C , if tanA:tanB :tanC=3:4:5, then the value of sinA sinB sinC is equal to (a) 2/(sqrt(5)) (b) (2sqrt(5))/7 (2sqrt(5))/9 (d) 2/(3sqrt(5))

In a triangle tanA+tanB+tanC=6 and tanAtanB=2 , then the values of tanA, tanB and tanC are

{:A=[(1,2,2),(2,1,-2),(a,2,b)]:} is a matrix and AAT=91, then the ordered pair (a,b) is equal to

if Agt0,Bgt0 and A+B=pi/3 then the maximum value of tanA.tanB is (a) 1/sqrt3 (b) 1/3 (c) 1/2 (d) sqrt3