Pressure over ideal binary liquid mixture containing 10 moles each of liquid A and B is gradually decreased isothermally. If `"P"_("A")^(@)=200"mm Hg " "and"" P"_("B")^(@)=100"mm Hg,`" find the pressure at which half of the liquid is converted into vapour.

A mixture contains 1 mole of volatile liquid A ("P"_("A")^(0)=80"mm Hg"). and 3 moles of volatile liquid B ("P"_("A")^(0)=80"mm Hg"). If solution behaves ideally, the total vapour pressure of the distillate is

A mixture contains 1 mole of volatile liquid A (P_(A)^(@) =100mm Hg) and 3 moles of volatile liquid B (P_(B)^(@) =80 mm Hg). If solution behaves ideally, the total vapour pressure of the distillate is :

Liquids A (p_(A)^(@)=360" mm Hg") and B(p_(B)^(@)=320" mm Hg") are mixed. If solution has vapour pressure 340 mm Hg, then mole fraction of B will be

4 mole of pure liquid A (P_(A)^(0)=80mm of Hg) and 6 mole of pure liquid B (P_(B)^(0)=100mm of Hg) are mixed . The vapour pressure of the resulting solution is found to be 90 mm of Hg then

At 300 K the vapour pressure of an ideal solution containing 1 mole of liquid A and 2 moles of liquid B is 500 mm of Hg. The vapour pressure of the solution increases by 25 mm of Hg, if one more mole of B is added to the above ideal solution at 300K. Then the vapour pressure of A in its pure state is

A 300 K the vapour pressure of an ideal solution containing 1 mole of liquid A and 2 moles of liquid B is 500 mm of Hg. The vapour pressure of the solution increases by 25 mm of Hg if one more mole of B is added to the above ideal solution at 300 K. Then vapour pressure of A in its pure state is :

If same amount of gas is trapped over liquid (a) and liquid (b) in following containers. Assuming temperature and cross-sectional area of container are same. P_(atm)=760mm Hg,d_(Hg)=13.6 g//mL Find the pressure (in cm Hg) of gas over the liquid (b).

Two liquids A and B with vapour pressures 400mm Hg and 600mm Hg respectively formed a binary ideal liquid mixure shown in the following diagram . (Temepature =constant) If the mole fraction of 'A' in the vapour phase is 0.5 , What is the optimum pressure , above which the vapour phase can start condensig back into liquid.

Total vapour pressure of mixture of 1 mole of volatile component A (P_(A)^(@)=100 mm Hg) and 3 mole of volatile component B (P_(B)^(@)=80 mm Hg) is 90 mm Hg . For such case :