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Show that ""(92)^(238)U can not spontane...

Show that `""_(92)^(238)U` can not spontaneously emit a proton. Given:
`""_(92)^(238)U` = 238.05079u, `""_(91)^(237)Pa` = 237.05121u `""_(1)^(1)H` = 1.00783u

Text Solution

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`""_(92)^(238)Urarr ""_(91)^(237)Pa+""_(1)^(1)H+Q`
`:. Q=[M_(u)-M_(Pa)-M_(H)]c ^(2)`
`=[238.05079-237.05121-1.00783]uzzx^x(2)`
`=-0.00825uzz931.5 (MaV)/(u)`
`=-7.68 MeV`
`:. QltO` , therefore it anc't proceed spontaneously. We will have to supply energy of 768MeV to ``""_(92)^(238)U` nucleus ot make it emit proton.
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