(a) Draw the structure of the following:
(i) `BrF_(3)`
(ii) `XeO_(3)`
(b) Answer the following:
(i) Why is `NH_(3)` more basic than `PH_(3)`?
(ii) Why are halogens strong oxidisin agents?
(iii) Draw the structure of `XeOF_4`

Explanation

(a) (i) N/A
(ii)
(b) (i) In `NH_3`, N has small size and the lone pair is concentration on a small region and electron density on it is maximum. So it has greater electron releasing tendency. But the size of P is large and the electron density of the lone pair is les. As a result, it has lesser tendency to donate electron pair. hence, `NH_(3)` is basic while `PH_(3)` is onluy feebly basic.
(ii) Halogens have strong tendency to accept electrons and therefore, act as strong oxidising agents. their oxidising power decreases from `F_(2)` to `I_(2)`.
(iii) N/A