If `a=cos3` and `b=sin8` then 1) a>0,b>0 2)ab<0 3)a>b 4)ab>0

A : The maximum area of the triangle formed by the points (0, 0), (a cos theta, b sin theta), (a cos theta, -b sin theta) is (1)/(2)|ab| . R : Maximum value of sin theta is 1.

If A=sin45^(0)+cos45^(0) and B=sin44^(0)+cos44^(0) then (a)A>B(b)A=B

Let F(a)=[(cos a,-sin a,0),(sin a, cos a, 0),(0,0,1)] and G(B)=[(cos B,0,sin B),(0,1,0),(-sin B,0,cos B)] " Show that " [F(a).G(B)]^(-1)=G(-B).F(-a) .

The value of the integral int_0^(pi/4) dx/(a^2cos^2x+b^2sin^2x) (A) 1/(ab)tan^-1(b/a)(a,bgt0) (B) 1/(ab)tan^-1(b/a)(a,blt0) (C) pi/4(a=1,b=1) (D) none of these

The value of the integral int_0^(pi/4) dx/(a^2cos^2x+b^2sin^2x)= (A) 1/(ab)tan^-1(b/a)(a,bgt0) (B) 1/(ab)tan^-1(b/a)(a,blt0) (C) pi/4(a=1,b=1) (D) none of these

If I=[(1,0),(0,1)]=J[(0,1),(-1,0)] and B=[(cos theta, sin theta),(-sin theta, cos theta)] then B=

If cos(A+B) = 0 and sin(A-B) = 1/2, then the value of B is: (Given 0^@ यदि cos(A+B) = 0 और sin(A-B) = 1/2, B का मान है:

if a=cos 0 + i sin 0,=cos 20 -i sin 20, c= cos3 0 + I sin 3 0 and if |{:(a,,b,,c),(b,,c,,a),(c,,a,,b):}| =0 then