`sqrt(3) ( 1 + 2costheta) = 4 sintheta`

(2+sqrt(3))costheta =1 - sintheta

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = sqrt2 sintheta} be two sets. Then:

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = 12 sintheta} be two sets. Then:

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = 12 sintheta} be two sets. Then:

(sintheta)/(1+costheta) is equal to (a) (1+costheta)/(sintheta) (b) (1-costheta)/(costheta) (c) (1-costheta)/(sintheta) (d) (1-sintheta)/(costheta)

Solve sqrt(3)costheta+sintheta=sqrt(2) .

sqrt(3)costheta+sintheta=2

sintheta - sqrt(3)costheta =1

If (2+sqrt(3))costheta=1-sintheta , then one general value is: