If `360 = 2^x**3^y**5^z` then `x+y+z = `

solve 3x - 2y + z = 1 2x + y- 5z = 2 x- y - 2z = 3.

If 2x+3y=5, 2y+z=3, and x+5y+z=3 , then x =

If x+y+z = 360 and x:y:z = 4:3:2, then the value of y+z-x is : यदि x+y+z = 360 तथा x:y:z = 4:3:2 है, तो y+z-x का मान कितना है ?

The system 2x + 3y + z= 5, 3x + y + 5z =7, x + 4y -2z=3 has

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

Add: 5x - 8y + 2z, 3z - 4y - 2x, 6y - z - x and 3x - 2z - 3y

If x!=y!=z and |x x^2 1+x^3 y y^2 1+y^3 z z^2 1+z^3|=0 , then prove that x y z=-1 .