If `2x+3y-5z = 7, x + y + z = 6 , 3x-4y+2z = 1`, then `x=`

The system 2x + 3y + z= 5, 3x + y + 5z =7, x + 4y -2z=3 has

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

The lines x + y + z - 3 = 0 = 2x - y + 5z - 6 and x - y - z + 1 = 0 = 2x + 3y + 7z - k are coplanar then k equals

Find the angle between the planes : (i) 3 x - 6y - 2z = 7 " " 2x + y - 2z = 5 (ii) 4 x + 8y + z = 8 " " and y + z = 4 (iii) 2 x - y + z =6 " " and x + y + 2z = 7 .

Solve using matrices, for x,y and z: 2x-y-z = 7, 3x+y - z = 7, x + y - z = 3.

if 3x-4y+2z= -1, 2x+3y+5z=7, x+z=2, then x=

3x+4y+7z=4, 2x+y+ 3z= 3, x + 2y +3z =8.

Add 2x - 3y + z , 5y - x + 7z and 3x - y - 6z.