To double the length of a iron wire having `0.5 cm^(2)` area of cross-section, the required force will be `(Y = 10^(12) "dyne/cm"^(2))`

Determine the force required to double the length of the steel wire of area of cross-section 5 xx 10^(-5) m^(2) . Give Y for steel = 2 xx 10^(11) Nm^(-2) .

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A force F doubles the length of wire of cross-section a The Young modulus of wire is

A wire of length 50 cm and cross sectional area of 1 sq. mm is extended by 1mm . The required work will be (Y=2xx10^(10) Nm^(-2))

A wire of length 50 cm and cross sectional area of 1 sq. mm is extended by 1mm . The required work will be (Y=2xx10^(10) Nm^(-2))

On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross section 2 mm^2 , the force required is [Y for steel =2.2xx10^11(N)/(m^2) ]

Calculate the conductivity of a wire of length 200 cm, area of cross-section 2cm^2 and of resistane 5xx10^4Omega .