If `cos (tan ^(-1) (sin (cot^ (-1) sqrt(3)))) =y`, then

cos[tan^(-1) {sin(cot^(-1) x)}] =

cos [ tan^(-1){sin (cot^(-1)x)}] =

If: cos(tan^(-1)x)=sin (cot^(-1).(3)/(4)), then : x =

Solve : cos(tan^(-1)x)=sin(cot^(-1)""(3)/(4))

Solve cos(tan^-1x) = sin(cot^-1 (3/4))

a=sin^(-1)(-(sqrt(2))/(2))+cos^(-1)(-(1)/(2)) and b=tan^(-1)(-sqrt(3))-cot^(-1)(-(1)/(sqrt(3))) ,then

If cot^(-1)(sqrt(cos1))-tan^(-1)(sqrt(cos1))=alpha then the value of sin alpha is -

If a=sin^(-1) (-sqrt2/2)+cos^(-1) (-1/2) and b=tan^(-1) (-sqrt3)-cot^(-1) (-1/sqrt3) , then

If =cos ec[tan^(-1){cos(cot^(-1)(sec(sin^(-1)a)))}] and y=sec[cot^(-1){sin(tan^(-1)(cos ec(cos^(-1)a)))}]