`(2^(3)+2^(6)+2^(8)+2^(-3))`

If root3((3^(6) xx 4^(3) xx 2^(6))/(8^(9) xx2^(3)))=(3/8)^(k) ,then k = _______ .

3sqrt((3^(6)xx4^(3)xx2^(6))/(8^(9)xx2^(3)) =____________

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

(2)/(3)+-(6)/(8)+(-(3)/(10))

Evaluate: (i) ((5)/(3)) ^(2 ) xx ((5)/(3)) ^(2) (ii) ((5)/(6))^(6) xx ((5)/(6)) ^(-4) (iii) ((2)/(3)) ^(-3) xx ((2)/(3)) ^(-2) (iv) ((9)/(8)) ^(-3) xx ((9)/(8)) ^(2)

Evaluate the following : {(5^(2)+12^(2))^(1)}^(3)( ii) {(6^(2)+8^(2))^(1)}^(3)

Simplify 6sqrt((27)^(-2/3)+(8)^(-2/3))

Simplify : (a-3)^(3) + 6(a-3)^(2)+12(a-3)+8

Solve ((9.8)^(3)-(6.8)^(3))/(9.8^(2)+9.8xx6.8+6.8^(2))