`sqrt(a^3b^4)xxsqrt(a^6b^3)`

sqrt(a^(3)b^(4))xx sqrt(a^(6)b^(3))

If a,b,c are positive real numbers sqrt(a^-1b)xxsqrt(b^-1 c)xxsqrt(c^-1 a) is equal to

3sqrt(13824)xxsqrt(?)=864

sqrt(a)xxsqrt(b)nesqrt(ab) : if both a and b are negative. It is treu?

If x = (sqrt(2a + 3b)+sqrt(2a - 3b))/(sqrt(2a + 3b) - sqrt(2a - 3b)) , show that 3bx^(2) - 4ax + 3b = 0 .

Solve for x. x=(sqrt(384))/(sqrt2xxsqrt3)

The following are the steps involved in finding the value of a+b from (2+sqrt(3))/(2-sqrt(3))=a+bsqrt(3) . Arrange them in sequential order. (A) (2^(2)+(sqrt(3))^(2) + 2xx2xxsqrt(3))/(2^(2)-(sqrt(3))^(2))=a+bsqrt(3) (B) a+b=7+4=11 (C) ((2+sqrt(3))(2+sqrt(3)))/((2-sqrt(3))(2+sqrt(3)))=a+bsqrt(3) (D) (7+4sqrt(3))/(4-3)=a+bsqrt(3) (E) a=7 and b=4