The incident ray is along the line `3x-4y-3=0` and the reflected ray is along the line `24 x+7y+5=0.` Find the equation of mirrors.

The incident ray is along the line 3x-4y-3=0 and the reflected ray is along the line 24x+7y+5=0. Find the equation of mirrors.

A ray of light along the line x- 2y + 5 = 0 is reflected from the line 3x - 2y + 7= 0 . Find the equation of the line containing the reflected ray .

A light ray coming along the line 3x+4y=5 gets reflected from the line a x+b y=1 and goes along the line 5x-12 y=10. Then,

A light ray coming along the line 3x+4y=5 gets reflected from the line ax+by=1 and goes along the line 5x-12y=10. Then,

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y-5=0, the ray is reflected from it .Find the equation of the line containing the reflected ray.

A ray of light travels along the line 2x-3y+5=0 and strikes a plane mirror lying along the line x+y=2 . The equation of the straight line containing the reflected ray is

A ray of light along the line x-2y+5=0 is reflected from the line 3x-2y+7=0.Fidn the equations of the line containing the reflected ray.

A ray of light is incident along a line which meets another line 7x-y+1=0 , at the point (0,1). The ray is then reflected from this point along the line y+2x=1 . Then the equation of the line of incidence of the ray of light is

[" 16.A ray travelling along the line "3x-4y=5" after being reflected from a line " "Y" travels along the line "],[5x+12y=13" .Then the equation of the line "'l" is "],[[" 1) "x+8y=0," 2) "x-8y=0," 3) "32x+4y+65=0," 4) "32x-4y+65=0]]