There are 5 bails numbered 1 to 5 and 5 boxes numbered 1 to 5. The balls are kept in the boxes one in each box. The probability that exactly 2 balls are kept in the corresponding numbered boxes and the remaining 3 bails in the wrong boxes, is

12 balls are kept in 3 different boxes, then the probability that the box will contain 3 balls is -

Six different balls are put in three different boxes, no box being empty. The probability of putting balls in the boxes in equal numbers is

5 different balls are placed in 5 different boxes randomly. Find the probability that exactly two boxes remain empty. Given each box can hold any number of balls.

5 different balls are placed in 5 different boxes randomly. Find the probability that exactly two boxes remain empty. Given each box can hold any number of balls.

5 different balls are placed in 5 different boxes randomly. Find the probability that exactly two boxes remain empty. Given each box can hold any number of balls.

Six different balls are put in three different boxes,no box being empty.The probability of putting balls in the boxes in equal numbers is

There are 6 red and 8 green balls in a bag. 5 balls are drawn at random and placed in a red box. The remaining balls are placed in a green box. What is the probability that the number of red balls in the green box plus the number of green balls in the red box is not a prime number?

There are 6 red and 8 green balls in a bag. 5 balls are drawn at random and placed in a red box. The remaining balls are placed in a green box. What is the probability that the number of red balls in the green box plus the number of green balls in the red box is not a prime number?

There are 6 red and 8 green balls in a bag. 5 balls are drawn at random and placed in a red box. The remaining balls are placed in a green box. What is the probability that the number of red balls in the green box plus the number of green balls in the red box is not a prime number?