A linear impulse `int Fdt` acts at a point `C` of the smooth rod `AB`. The value of `x` is so that the end `A` remains stationary just after the impact is

A uniform rod AB of length L and mass M is lying on a smooth table. A small particle if mass m strike the rod with velocity v_(0) at point C at a distance comes to rest after collision. Then find the value of x , so that point A of the rod remains stationary just after collision. .

A uniform rod AB of length L and mass M is lying on a smooth table. A small particle if mass m strike the rod with velocity v_(0) at point C at a distance comes to rest after collision. Then find the value of x , so that point A of the rod remains stationary just after collision. .

A particle at rest is constrained to move on a smooth horizontal surface. Another identical particle hits the stationary particle with a velocity v at an angle theta=60^(@) with horizontal. If the particles move together, the velocity of the combination just after the impact is equal to

A particle at rest is constrained to move on a smooth horizontal surface. Another identical particle hits the stationary particle with a velocity v at an angle theta=60^(@) with horizontal. If the particles move together, the velocity of the combination just after the impact is equal to

A rod AB of length 2 m and mass 2 kg is lying on a smooth horizontal x-y plane with its centre at origin O as shown in figure. An impulse J of magnitude 10 N-s is applied perpendicular to AB at A. The distance of point P from centre of the rod which is at rest just after impact is

On a smooth horizontal plane, a rod PQ of length 6m and mass 2 kg is placed. The centre of the rod is placed at the origin of the coordinate axes. An impulse of 4N -S is applied at P perependicular to the length of the rod. Find the distance of a point form centre of the rod which is at rest after the impact (in metres)