The parametric equation of a parabola is `x=t^2+1,y=2t+1.` Then find the equation of the directrix.

The parametric equations of a parabola are x=t^(2)+1,y=2t+1. The Cartesian equation of its directrix is x=0 b.x+1=0 c.y=0 d.none of these

If y^(2)=-12x is the given equation of the parabola,then find the equation of the directrix.

If parametric representation of a parabola is x=2+t^(2) and y=2t+1 , then

The focal chord of the parabola y^(2)=ax is 2x-y-8=0. Then find the equation of the directrix.

If y^(2) = -12x is the given equation of the parabola, then find the equation of the directrix.

Find the parametric equation of the parabola (x-1)^(2)=-16(y-2)

The Cartesian equation of the curve whose parametric equations are x=t^(2) +2t+3 and y=t+1 is a parabola (C) then the equation of the directrix of the curve 'C' is.(where t is a parameter)

If the parabola y^(2)=ax passes through (1,2) then the equation of the directrix is

Find the equation of a parabola whose focus is (-8,-2) and equation of directrix is y=2x-9.