The arithmetic mean of 10 observations is 45. If one of the obsservations, 54, is deleted, then find the mean of the remaining observations.

The mean of 50 observations is 36. If its two observations 30 and 42 are deleted,then the mean of the remaining observations is

The mean of 10 observation is 15. If one observation 15 is added, then find the new mean.

The arithmetic mean of 12 observations is 15. If two observations 20 and 25 are removed then the arithmetic mean of remaining observations is

The mean of 50 observations is 36. If two observations 30 and 42 are deleted, then mean of the remaining observations is

AM of 11 observations is 17.5 and one observation 15 is deleted from the data then the mean of remaining observations is______

The arithmetic mean of 13 observations is 60. If one of the observation 50 is deleted and another observation 63 is included. Find the new arithmetic mean. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) New sum of observations =780-50+63=793 (B) The sum of the observation =13xx60=780 (C) :. New arithmetic mean =793/13 (D) The required mean =61

The mean of 10 observations is 12. If mean of first 6 observations is 13. Find the mean of remaining 4 observations.

The mean of 10 observations is 12. If mean of first 6 observations is 13. Find the mean of remaining 4 observations.