If `x=tan t-t,y=sec t,` then `y^3y_2+(y_1)^4=`

If x = tan tt, y = sec t, then y ^ (3) y_ (2) + (y_ (1)) ^ (4) =

If x=3tan t and y=3sec t then find (d^(2)y)/(dx^(2)) at x=(pi)/(4)( a) 3( b) (1)/(6sqrt(2))(c)1(d)(1)/(6)

If x = 3 tant and y = 3 sec t, then the value of (d^2y)/(dx^2)" at" t=pi/4 is

If x = 3 tant and y = 3 sec t, then the value of (d^2y)/(dx^2)" at" t=pi/4 is

If x = 3 tant and y = 3 sec t, then the value of (d^2y)/(dx^2)" at" t=pi/4 is

If x = 3 tant and y = 3 sec t, then the value of (d^2y)/(dx^2)" at" t=pi/4 is

If x = 3 tan t and y = 3 sec t then the value of (d^2y)/(dx^2) at t = pi/4 , is 1/(ksqrt2) . The value of k is _________.

If x=2t+3t^(2),y=t^(2)+2t^(3)," then: "(y_(1))^(2)+2(y_(1))^(3)=

If x^2+y^2=t-1/t and x^4+y^4=t^2+1/t^2, then x^3y (dy)/(dx)= (a) 0 (b) 1 (c) -1 (d) none of these