The focal chord of the parabola `y^2=a x` is `2x-y-8=0` . Then find the equation of the directrix.

If (2,-8) is at an end of a focal chord of the parabola y^(2)=32x, then find the other end of the chord.

The parametric equation of a parabola is x=t^(2)+1,y=2t+1. Then find the equation of the directrix.

If one end of a focal chord "AB" of the parabola y^(2)=8x is at "A((1)/(2),-2) " then the equation of the tangent to it at "B" is ax+by+8=0" .Find a+b

If y^(2)=-12x is the given equation of the parabola,then find the equation of the directrix.

If y^(2) = -12x is the given equation of the parabola, then find the equation of the directrix.

(1/2,2) is one extremity of a focal of chord of the parabola y^(2)=8x The coordinate of the other extremity is

If (-1,-2sqrt2) is one of exteremity of a focal chord of the parabola y^(2)=-8x, then the other extremity is

Let one end of focal chord of parabola y^2 = 8x is (1/2, -2) , then equation of tangent at other end of this focal chord is

The directrix of the parabola y^(2) = - 8x" is", x = 2 .