If `(1+i)(1+2i)(1+3i)...(1+n i)=a+i b ,` then `2. 5. 10. 17... (1+n^2\ )=` a. `a-i b` b. `a^2-b^2` c. `a^2+b^2` d. none of these

If (1+i)(1+2i)(1+3i)...(1+n i)=a+i b , then the value of; 2. 5. 10. 17... (1+n^2\ ) will be (a) . a-i b (b) . a^2-b^2 (c) . a^2+b^2 (d) . none of these

If (1+i)(1+2i)(1+3i)(1+ni)=a+ib then 2.5.10.17(1+n^(2))=a-ibba^(2)-b^(2)c*a^(2)+b^(2)d none of these

If (1 + i) (2 +i) (3 + i)…..(n+i)=a+ib ,show that 2.5.10…. (n^2+1)=a^2+b^2

If (1+i)(2+i)(3+i)...(n+i)=a+ib show that, 2*5*10...(n^(2)+1)=a^(2)+b^(2).

If (1+i)(2+i)(3+i)………(n+i)=a+ib then show that 2.5.10……….(n^2+1)=a^2+b^2

If (1+i)(1+2i)(1+3i)........(1+n i)=a+i b ,t h e n2xx5xx10 ....(1+n^2) is equal to sqrt(a^2+b^2) (b) sqrt(a^2-b^2) (c) a^2+b^2 (d) a^2-b^2 (e) a+b

If (1+i)(1+2i)(1+3i)......(1+ni)=a+ib,then2xx5xx10...(1+n^(2)) is equal to sqrt(a^(2)+b^(2))(b)sqrt(a^(2)-b^(2))(c)a^(2)+b^(2)(d)a^(2)-b^(2)(e)a+b

The value of (1+i)(1+i^2)(1+i^3)(1+i^4) is a. 2 b. 0 c. 1 d. i

a+ib=(1+i)(1+2i)(1+3i) then a^(2)+b^(2)=

(1+2i+3i^2)/(1-2i+3i^2) equals a. i b. -1 c. -i d. 4