The amplitude of a particle performing `SHM` is 'a'. The displacement at which its velocity will be half the maximum velocity is

A particle is executing S.H.M. with amplitude 'A' and maximum velocity V_(m) . The displacement at which its velocity is half of the maximum velocity is

A particle oscillating in simple harmonic motion has amplitude 'a'. The distance from the mean position at which its velocity will be one half of the maximum velocity is

A simple harmonic oscillator has amplitude 2 A and maximum velocity 2 V. Then its displacement at which its velocity is V and the velocity at displacement A are

Find the value of the displacement of a particle in S.H.M. when its velocity is half the maximum velocity.

A particle is performing SHM. At what distance from mean position, the velocity of the particle becomes half of the maximum velocity ?

A graph between velocity and displacement of a particle performing SHM is shown. Find the acceleration when the particle is at half of maximum displacement from mean position.

A particle executes S.H.M with amplitude 'A' If the displacement y=A//2 which of the following will be half of its maximum value

The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

The total energy of a particle of mass 200 gm. performing S.H.M is 10^( -3) J , if the amplitude is 5cm. The maximum velocity is