x+2y>=10,3x+4y<=24,x>=0,y>=0

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+5=0 and 3x+4y-10=0 is equal to

Given the four lines with the equations 'x+2y-3=0,3x+4y-7=0,2x+3y-4=0,4x+5y-6=0, then

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then:

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+4y+5=0 and 3x+4y-10=0 is equal to

2x+3y=0 3x+4y=5

Prove that the three lines 5x+3y-7=0, 3x-4y=10, and x+2y=0 meet in a point.

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

5x-2y-10=0,10x-4y-20=0 these are………lines.