The abscissa and ordinates of the endpoints `Aa n dB` of a focal chord of the parabola `y^2=4x` are, respectively, the roots of equations `x^2-3x+a=0` and `y^2+6y+b=0` . Then find the equation of the circle with `A B` as diameter.

If abscissas and ordinates of points A , B are roots of equation x^(2) - 3x + 2 = 0 " and " y^(2) - 7y + 12 = 0 , then equation of circle with AB as a diameter is

The focal chord of the parabola y^(2)=ax is 2x-y-8=0. Then find the equation of the directrix.

If y=2x is the chord of the circle x^(2)+y^(2)-4x=0, find the equation of the circle with this chord as diameter.

The abscissae and ordinates of the points A and B are the roots of the equations x^(2)+2ax+b=0 and x^(2)+2cx+d=0 respectively,then the equation of circle with AB as diameter is

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.

The abscissa of the two points A and B are the roots of the equation x^(2)+2ax-b^(2)=0 and their ordinates are the roots of the equation x^(2)+2px-q^(2)=0. Find the equation of the circle with AB as diameter.Also,find its radius.

If the abscissa and ordinates of two points P and Q are the roots of the equations x^(2)+2ax-b^(2)=0 and x^(2)+2px-q^(2)=0 respectively,then find the equation of the circle with PQ as diameter.