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[(1)/(2x)+(1)/(3)-22],[(1)/(3x)+(1)/(2y)...

[(1)/(2x)+(1)/(3)-22],[(1)/(3x)+(1)/(2y)=(13)/(6)]

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(1)/(3+(1)/(2-(1)/(2)))+(17)/(22)

((3)/(x))^((1)/(5))+((x)/(3))^((1)/(7))=22(2)/(3) ,find difference of all possible value of x.

The x-coordinates of the vertices of a square of unit area are the roots of the equation x^2-3|x|+2=0 . The y-coordinates of the vertices are the roots of the equation y^2-3y+2=0. Then the possible vertices of the square is/are (a)(1,1),(2,1),(2,2),(1,2) (b)(-1,1),(-2,1),(-2,2),(-1,2) (c)(2,1),(1,-1),(1,2),(2,2) (d)(-2,1),(-1,-1),(-1,2),(-2,2)

The x-coordinates of the vertices of a square of unit area are the roots of the equation x^2-3|x|+2=0 . The y-coordinates of the vertices are the roots of the equation y^2-3y+2=0. Then the possible vertices of the square is/are (a)(1,1),(2,1),(2,2),(1,2) (b)(-1,1),(-2,1),(-2,2),(-1,2) (c)(2,1),(1,-1),(1,2),(2,2) (d)(-2,1),(-1,-1),(-1,2),(-2,2)

Value of lambda for which (lambda,lambda^2) lies between the lines |x+2y|=3 is (a) ( -1/2,2) (b) (-3/2,2) (c) (-3/2,1) (d) (-1,3/2)

Which of the following are identity relations on set A={1,2,3} R_(1)={(1,1),(2,2)},R_(2)={(1,1),(2,2),(3,3),(1,3)},R_(3)={(1,1),(2,2),(3,3)}

The x-coordinates of the vertices of a square of unit area are the roots of the equation x^(2)-3|x|+2=0 .The y -coordinates of the vertices are the roots of the equation y^(2)-3y+2=0. Then the possible vertices of the square is/are (1,1),(2,1),(2,2),(1,2)(-1,1),(-1,-1),(1,2),(2,2)(-2,1),(-1,-1),(-1,2),(-2,2)

If A=[(4,1,0),(1,-2,2)],B=[(2,0,-1),(3,1,4)],C=[(1),(2),(-1)] and (3B-2A)C+2X=O then X=