Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m/s and 1 m/s, respectively. They collide and after the collision , the first object moves at a velocity of 1.67 m /s Determine the velocity of the second object.
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Mass of one of the objects `M_1=100 g =0.1 kg`. Mass of the other object `M_2 =200 g=0.2 kg` Velocity of `M_1` Before collision `V_1 =2m//s` Velocity of `M_2` before collision ,`V_2=1 m//s` Velocity of `M_2` after collision `V_3=1.67m//s` Veloctiy of `M_2` after collision `V_4`. according to the law of conservation of momentum Total momentum before collision= Total momentum after collision Therefore `m_1v_1+m_2v_2=m_1v_3+m_2v_4` `2(0.1)+1(0.2)=1.67(0.1)+v_4(0.2)` `0.4 =0.167+0.2 v_4` `V_4 =1.165 m//s` Hence, the velocity of the second object becomes 1.165 m/s after the collision.
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