" (iv)."2x-2y-2=0,4x-4y-5=0

Solution to 2x-2y-2=0, 4x-4y-5=0 is………..

Find the centre and radius of each of the following circle : (i) x^(2)+y^(2)+4x-4y+1=0 (ii) 2x^(2)+2y^(2)-6x+6y+1=0 (iii) 2x^(2)+2y^(2)=3k(x+k) (iv) 3x^(2)+3y^(2)-5x-6y+4=0 (v) x^(2)+y^(2)-2ax-2by+a^(2)=0

The perimeter of a parallelogram whose sides are represented by the lines x+2y+3=0 , 3x+4y-5=0,2x+5=0 and 3x+4y-10=0 is equal to

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

The equation of the circle which has normals (x-1).(y-2)=0 and a tangent 3x+4y=6 is (a) x^2+y^2-2x-4y+4=0 (b) x^2+y^2-2x-4y+5=0 (c) x^2+y^2=5 (d) (x-3)^2+(y-4)^2=5

If the origin is shifted to the point (1,2) then what will be the transform equation of the following equations, it is given that the new and old axes are parallel : (i) x^(2)+y^(2)-2x-4y=0 (ii) 2x^(2)-y^(2)-4x+4y-3=0 (iii) x^(2)+xy-2y^(2)-4x+7y-5=0 (iv) 3x+y=6

2x+3y=0 3x+4y=5

From the points (3, 4), chords are drawn to the circle x^2+y^2-4x=0 . The locus of the midpoints of the chords is (a) x^2+y^2-5x-4y+6=0 (b) x^2+y^2+5x-4y+6=0 (c) x^2+y^2-5x+4y+6=0 (d) x^2+y^2-5x-4y-6=0