Consider the system of equations
`x+y+z=6`
`x+2y+3z=10`
`x+2y+lambdaz =mu`
the system has infinite solutions if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu The system has no solution if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu The system has no solution if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has unique solution if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has unique solution if

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu the system has unique solution if (a) lambda ne 3 (b) lambda =3, mu =10 (c) lambda =3 , mu ne 10 (d) none of these

Consider the system of equations x+y+z=6 x+2y+3z=10 x+2y+lambdaz =mu The system has no solution if (a) lambda ne 3 (b) lambda =3, mu =10 (c) lambda =3, mu ne 10 (d) none of these

Consider the system of equations x+y+z=5 x+2y+lamda^2z=9 x+3y+lamdaz=mu

Consider the system of equation x+y+z=6,x+2y+3z=10 ,a n dx+2y+lambdaz=mudot Statement 1: if the system has infinite number of solutions, then mu=10. Statement 2: The determinant |(1 ,1, 6), (1, 2, 10),(1, 2,mu)| = 0 for mu=10.

Consider the system of equation x+y+z=6,x+2y+3z=10 ,a n dx+2y+lambdaz=mudot Statement 1: if the system has infinite number of solutions, then mu=10. Statement 2: The determinant |1 1 6 1 2 10 1 2mu|=0formu=10.