[" 26."x+y=5xy],[quad 3x+2y=13xyquad (x!=0,y!=0]

Solve the following system of equations: x+y=5xy,quad 3x+2y=13xy,quad x!=0,quad y!=0

x + y = 5 xy , 3x + 2y = 13 xy ( x ne 0, y ne 0 )

Solve: 3 (2x+ y ) = 7xy 3(x+ 3y ) = 11xy , x ne 0 , y ne 0

if y + x = 5xy , y - x = -xy

In the equations 3x+2y=13xy and 4x-5y=2xy, the values of x and y that satisfy the equations are

4 x + 6y = 3 xy , 8x + 9 y = 5xy ( x ne 0 , y ne 0 )

Solve for x and y, by reducing the following equations in a pair of linear equations : 2x + 3y = 5xy and 3x - 2y = xy.

xy^(2)-x^(2)y-5=0

Group the like terms from the algebraic expressions given: 2x, y, 12xy, 13y^2 , -5x, 18y, -4xy, -2y^2 , 21x^2y , 3x, 3xy, -xy, -y, -6x^2 , -15x^2 .

Add (2x^2+5xy+2y^2), (3x^2-2xy+5y^2) and (-2x^2+8xy+3y^2)