Home
Class 11
MATHS
Find the equation of a parabola having i...

Find the equation of a parabola having its focus at `S(2,0)` and one extremity of its latus rectum at (2, 2)

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the equation of the parabola having (3,-6) and (3,6) as the extremities of the latus rectum .

Find the equation of a parabola having its vertex at A(1,0) and focus at S(3,0) .

Find the equation of the parabola having vertex at (0, 0) and focus at (-2, 0) .

Find the equation of parabola (i) having its vertex at A(1,0) and focus at S(3,0) (ii) having its focus at S(2,5) and one of the extremities of latus rectum is A (4,5)

Find the equation of parabola (i) having its vertex at A(1,0) and focus at S(3,0) (ii) having its focus at S(2,5) and one of the extremities of latus rectum is A (4,5)

Find the equation of the parabola whose vertex is (2,3) and the equation of latus rectum is x=4. Find the co-ordinates of the point of intersection of this parabola with its latus rectum.

Find the equation of parabola (i) having focus at (0,-3) its directrix is y = 3. (ii) having end points of latus rectum (5,10) and (5,10) and which opens towards right. (iii) having vertex at origin and focus at (0,2)

Find the equation of parabola (i) having focus at (0,-3) its directrix is y = 3. (ii) having end points of latus rectum (5,10) and (5,-10) and which opens towards right. (iii) having vertex at origin and focus at (0,2)

The vertex of a parabola is (2,2) and the coordinats of its two extrremities of latus rectum are (-2,0) and (6,0). Then find the equation of the parabola.