" The slope of normal to the curve "x=sqrt(t)" and "y=t-(1)/(sqrt(t))" at "t=4" is."

The slopee of normal to the curve x=sqrt(t) and y=t-(1)/(sqrt(t)) at t=4 is . . .

The equation of normal to the curve x=(1)/(t), y=t-(1)/(t)" at "t=2 is

Equations of the tangent and normal to the curve x=sqrtt, y=t- (1)/(sqrt t) at the point t=4 are respectively

Slope of the normal to the curve x=a(t+sint),y=a(t-sint) is

Find the slope of the normal for the curve x= t^2 and y= 2t at t = 1.

Find the slope of the tangent to the curve x=2(t-sin t) and y = 2(1-cost) at t= (pi)/(4)

Find the slope of the tangent to the curve x=a((1-t^2)/(1+t^2)) and y= (2at)/(1+t^2) at t= (1)/(sqrt3)

The slope of the tangent to the curve x=at^3,y=at^4 at t=1 is