sin(B-C)/(2)=(b-c)/(a)cos(A)/(2)

In any triangle ABC, prove that (i) (a-b)/( c)=("sin"(A-B)/(2))/("cos"( C)/(2)) (ii) (b-c)/(a)=("sin"(B-C)/(2))/("cos"(A)/(2))

If a ,b ,c denote the lengths of the sides of a triangle opposite to angles A ,B ,C respectively of a A B C , then the correct relation among a ,b , cA ,Ba n dC is given by (b+c)sin((B+C)/2)=acos b. (b-c)cos(A/2)=asin((B-C)/2) c. (b-c)cos(A/2)=2asin((B-C)/2) d. (b-c)sin((B-C)/2)="a c o s"A/2

In any triangle ABC, prove that : sin frac (B-C)(2) = (b-c)/(a) cos frac (A)(2) .

In triangle ABC,a,b,c are the lengths of its sides and A,B,C are the angles of triangle ABC .The correct relation is given by (a) (b-c)sin((B-C)/(2))=a(cos A)/(2) (b) (b-c)cos((A)/(2))=as in(B-C)/(2)(c)(b+c)sin((B+C)/(2))=a(cos A)/(2)(d)(b-c)cos((A)/(2))=2a(sin(B+C))/(2)

For any triangle ABC, prove that : (a-b)/(c )=(sin((A-B)/(2)))/(cos((C)/(2)))

In any Delta ABC, prove that :(a-b)/(c)=(sin((A-B)/(2)))/(cos((c)/(2)))

For any triangle ABC ,prove that (a-b)/(c)=(sin((A-B)/(2)))/(cos(C)/(2))

Which of the following is true in a triangle ABC?(1)(b+c)sin((B_(C))/(2))=2a cos((A)/(2))(2+c)cos((A)/(2))=2a sin((B-C)/(2))

If a,b,c are sides opposte to the angles A,B , C then which of the following is correct (1)(b+c)cos((A)/(2))=a sin((B+C)/(2))(2)(b+c)cos((B+C)/(2))=a sin((A)/(2))(3)(b-c)cos((B-C)/(2))=a(cos A)/(2)(4)(b-c)cos((A)/(2))=a sin((B-C)/(2))

Theorem 4:sin A+sin B+sin C=4(cos A)/(2)(cos B)/(2)(cos C)/(2)