Home
Class 12
PHYSICS
[" Is de-Broglie wavelengt "],[" not mas...

[" Is de-Broglie wavelengt "],[" not mass 'M',is acceler "],[" ated with it will be (Asst "]

Promotional Banner

Similar Questions

Explore conceptually related problems

When electron with mass m is accelerated with volt V associated de-Broglie wavelength is lambda .When proton with mass M is accelerated with same voltage associated de-Broglie wavelength will be………

An electron of mass 'm', when accelerated through a potential V has de-Broglie wavelength lambda . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be:

An electron of mass 'm' is accelerated by a potential difference V and the corresponding de-Broglie wavelength is lamda The de Broglie wavelength of a proton of mass M if it is accelerated by the same potential difference is.

An electrono of mass m, when accelerated through a potential difference V, has de-Broglie wavelength lambda . The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be:

An electron of mass m when accelerated through a potential difference V has de - Broglie wavelength lambda . The de - Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

An electron of mass m when accelerated through a potential difference V has de - Broglie wavelength lambda . The de - Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

An electron of mass m , when accelerated through a potential difference V , has de Broglie wavelength lambda . The de Broglie wavelength associated with a proton of mass M , accelerated through the same potential difference, will be

An electron of mass m when accelerated through a potential difference V, has de Broglie wavelength lambda . The de Broglie wavelength associated with a proton of mass M accelerated through the same potential difference, will be :-

The de Broglie wavelength of an atom of mass m of a diatomic gas at temperature T will be :