` (iv) "12y^(2)-25y+12`

9y^(2)-12y+2=0

Factorise : (iv) 5x^(2) - 4xy - 12y^(2)

(i) 12x^(2) + 11x + 2 = 0 (ii) 25y^(2) + 15y+2 = 0

The Curve represented by the equation 12x^(2)-25xy+12y^(2)+10x+11y+2=0 is

The product of perpendiculars from origin to the pair of lines 12x^(2)+25xy+12y^(2)+10x+11y+2=0

Find the product of lengths of perpendiculars drawn from (2, 1) upon the lines 12x^(2)+25xy+12y^(2)+10x+11y+2=0

The product of perpendicular distances from the origin to the pair of straight lines 12x^(2)+25xy+12y^(2)+10x+11y+2=0

7(x-2y)^(2)-25(x-2y)+12

Multiply: 9x^(2)+25y^(2)+15xy+12x-20y+16 by 3x-5y+4