To prepare a tent of shaped a right circular cone, it needs 77 sq-metres of canvas. If the slant height of the tent be 700 cm. then find the area of the tent.

77 sq-cm tripal is required to make a right circular conical tent. If the slant height of the tent is 7m, then calculate the base area of the tent.

77 sq m tripal is required to make a right circular conical tent. If the slant height of the tant is 7 m then what is the area of the base of the tent?

The volume of a right circular conical tent is 1232c c . If the height of the tent be 24 metres, the area of the base of the cone will be .

Two make a right circular conical tent 22 metre broad canvas is required. It is height of the tent is 28 metre and the area of the base is 1386 sq. metre then how long convas is required to make the tant?

The lower part of a tent is of shape of a right circular cylinder , the height of which is 3.5 metres . The upper part of the the tent is of a shape of a right circular cone . If the total height of the tent be 9.5 metre and it its diameter of base be 5 metre , then how much quantity of tarpailin will be required to make 14 such tents ?

The area of canvas to be used in making the tent, is:

The lower part of a radius tent is a right circular cylinder and its upper part is a right circular cone . If the diameter of base of the tent be 105 metre , the height of the cylindrical part is 3 metre and the slant height of the conical part be 53 metre , then what quantity of canvas will be needed to make the tent ?

The cloth required to make a right circular conical tent is 188 4/7 sq meter. If the circumference of bae of the tent is 37 5/7 metre, find the slant height, radius ad height of the tent.

The lower part of a circus tent is a right circualr cylinder and its upper part is right circular cone. The diameter of the base of the tent is 56 m and height of the cylindrical part is 15 m. The total height of the tent is 60 m. How many square metres of canvas is required for the tent? Find the volume of the air space in tent (pi=(22)/7)